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What is the smallest positive integer \(x\) such that

Expert replies
by swerve » Sat Mar 16, 2019 9:41 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

What is the smallest positive integer \(x\) such that \(450x\) is the cube of a positive integer?

A. 2
B. 15
C. 30
D. 60
E. 120

The OA is D

Source: Manhattan Prep
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Source: — Problem Solving |

by Ian Stewart » Sun Mar 17, 2019 11:50 am
Prime factorize the 450:

450 = 50*9 = 2 * 3^2 * 5^2

To get a perfect cube, we need to multiply by a number that will make every exponent in the prime factorization into some multiple of 3. So the smallest thing we can multiply by is 2^2 * 3^1 * 5^1 = 60, since that will give us 2^3 * 3^3 * 5^3, which is the cube of (2)(3)(5).
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

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by Scott@TargetTestPrep » Tue Mar 19, 2019 6:00 pm
swerve wrote:What is the smallest positive integer \(x\) such that \(450x\) is the cube of a positive integer?

A. 2
B. 15
C. 30
D. 60
E. 120

The OA is D

Source: Manhattan Prep
We must remember that all perfect cubes break down to unique prime factors, each of which has an exponent that is a multiple of 3. So, let's break down 450 into primes to help determine what extra prime factors we need to make 450x a perfect cube.

450 = 45 x 10 = 9 x 5 x 5 x 2 = 3 x 3 x 5 x 5 x 2 = 5^2 x 3^2 x 2^1

In order to make 450x a perfect cube, we need two more 2s, one more 3, and one more 5. Thus, the smallest perfect cube that is a multiple of 450 is 5^3 x 3^3 x 2^3. In other words, 450x = (5^3)(3^3)(2^3). Thus:

x = (5^3 * 3^3 * 2^3)/450

x = (5^3 * 3^3 * 2^3)/(5^2 * 3^2 * 2^1)

x = 5^1 * 3^1* 2^2 = 60

Answer: D

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