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What is the smallest integer \(n\) for which \(25^n > 5^{12}?\)

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Re: What is the smallest integer \(n\) for which \(25^n > 5^{12}?\)

by Brent@GMATPrepNow » Sun Jan 10, 2021 6:16 am
Gmat_mission wrote: ↑
Fri Jan 08, 2021 1:55 am
 What is the smallest integer \(n\) for which \(25^n > 5^{12}?\)

(A) 6
(B) 7
(C) 8
(D) 9
(E) 10

Answer: B

Source: Official Guide
We have: 25^n > 5^12

To rewrite this inequality with the SAME base, we'll replace 25 with 5².
When we do so, we get: (5²)^n > 5^12
Apply the Power of a Power law to get: 5^(2n) > 5^12

This means that it must be the case that 2n > 12
Divide both sides of the inequality by 2 to get: n > 6

What is the smallest integer n for which 25^n > 5^12 ?
We now know that n > 6
So, 7 is the smallest possible INTEGER value that satisfies this inequality.

Answer: B

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Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Re: What is the smallest integer \(n\) for which \(25^n > 5^{12}?\)

by Scott@TargetTestPrep » Tue Jan 19, 2021 7:39 am
Gmat_mission wrote: ↑
Fri Jan 08, 2021 1:55 am
 What is the smallest integer \(n\) for which \(25^n > 5^{12}?\)

(A) 6
(B) 7
(C) 8
(D) 9
(E) 10

Answer: B

Source: Official Guide
Solution:

We re-express 25 as 5^2:

25^n > 5^12

5^(2n) > 5^12

When we have the same base, we can compare the exponents:

2n > 12

n > 6

The smallest integer greater than 6 is 7.

Answer: B

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