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What is the remainder?

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by suzeemunkee » Sun May 30, 2010 3:32 pm
What is the remainder when the positive integer x is divided by 3?

(1) When x is divided by 6, the remainder is 2.
(2) When x is divided by 15, the remainder is 2.

How do you determine remainders here?

(Got this from mba.com prep test.)

Thank you!
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by Haaress » Sun May 30, 2010 3:52 pm
What is the remainder when the positive integer x is divided by 3?

(1) When x is divided by 6, the remainder is 2.
(2) When x is divided by 15, the remainder is 2.

Question paraphrased: What is R in the equation x/3 = (I) Integer + (R) Remainder..

Stmt 1: x/6 = (I) Integer + (R) Remainder 2......where I is 1 , 2 , 3 etc

x = 6(I) + 2 .... 6(1) + 2 = 8 , 6(2) + 2 = 14 , 6(3) + 2 = 20 , 6(4) + 2 = 26...

So x = 8, 14, 20, 26 and when each of these integers is divided by 3 the remainder is 2. so suff.

Stmt 2: x/15 = I + 2 , so x is 17, 32, 47 etc..and when each of these integers is divided by 3 the remainder is 2. so suff.

The answer is D
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by suzeemunkee » Sun May 30, 2010 4:00 pm
Thank you!! I get it now :)
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by gmatjedi » Sun May 30, 2010 4:35 pm
hey, another approach:

st 1: x/6=q+2/6; x = 6q+2; 6q+2 / 3; r =2/3

st2: x/15=q+2/15; x=15q+2; 15q+2 / 3; r = 2/3

d
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by suzeemunkee » Sun May 30, 2010 4:47 pm
gmatjedi wrote:hey, another approach:

st 1: x/6=q+2/6; x = 6q+2; 6q+2 / 3; r =2/3

st2: x/15=q+2/15; x=15q+2; 15q+2 / 3; r = 2/3

d

This is really helpful - was wondering about the algebraic approach. Thank you!!
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