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by uptowngirl92 » Fri Oct 23, 2009 3:24 pm
When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 40, what is the remainder when k is divided by 7?

Options:1 2 3 4 5
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by pandeyvineet24 » Fri Oct 23, 2009 4:46 pm
Values of k, when its divided by 5
2,7,12,17,22,27,32,37

Values of k, when its divided by 6
5,11,17,23,29,35

17 is the common among the sets.


17 divided by 7 gives 3 as remainder
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by uptowngirl92 » Fri Oct 23, 2009 5:37 pm
thanks:)Even I had gotten it by plugging values..wanted to know if there is any other way of doing the problem..

taking the LCM maybe?
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by life is a test » Sat Oct 24, 2009 2:38 am
pandeyvineet24 wrote:Values of k, when its divided by 5
2,7,12,17,22,27,32,37

Values of k, when its divided by 6
5,11,17,23,29,35

17 is the common among the sets.


17 divided by 7 gives 3 as remainder
if you continue the sequence, 47 is also a common num but 47/7 does not = 3...
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by pandeyvineet24 » Sat Oct 24, 2009 4:27 am
life is a test wrote:
pandeyvineet24 wrote:Values of k, when its divided by 5
2,7,12,17,22,27,32,37

Values of k, when its divided by 6
5,11,17,23,29,35

17 is the common among the sets.


17 divided by 7 gives 3 as remainder
if you continue the sequence, 47 is also a common num but 47/7 does not = 3...
Hi life is a test, the question says that K is less than 40.
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