Hi AAPL,
While we're given a lot of information to work with, this question is mostly about recognizing the 'classic' right triangles involved and staying organized with how the various 'side lengths' relate to one another. To find the perimeter, we need to define the 'outside lines' of the shape.
-Since AF=10 and EF=6, we have a 3/4/5 right triangle that's been 'doubled', so AE = 8
-CDE is an EQUILATERAL triangle with sides of 3, so AC = 5
-AB = DE = 3 and triangle ABC is a 3/4/5 right triangle, so BC = 4
Now you have all of the perimeter side lengths: 3+4+3+3+6+10 = 29
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
