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What is the equivalent expression of

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What is the equivalent expression of

by Max@Math Revolution » Mon Apr 27, 2020 1:08 am

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[GMAT math practice question]

What is the equivalent expression of (1/x+y+z)(1/x+1/y+1/z)(1/xy+yz+zx)(1/xy+1/yz+1/zx)?

A. 1/x+y+z
B. 1/xy+yz+zx
C. 1/xyz
D. (1/xyz)^2
E. xy+yz+zx/x+y+z
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Re: What is the equivalent expression of

by Max@Math Revolution » Wed Apr 29, 2020 4:27 am
=>

(1/x+y+z)(1/x+1/y+1/z)(1/xy+yz+zx)(1/xy+1/yz+1/zx)
=(1/x+y+z)(xy+yz+zx/xyz)(1/xy+yz+zx)(x+y+z/xyz)
=(1/xyz)^2

Therefore, D is the answer.
Answer: D
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