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What is the distance?

Expert replies
by rrobiinn » Wed Sep 19, 2012 10:56 pm
If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?
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Source: — Problem Solving |

by rrobiinn » Wed Sep 19, 2012 11:05 pm
rrobiinn wrote:If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?
.

I solved it just now. Couldn't find the post delete button.
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by KapilKapoor » Wed Sep 19, 2012 11:07 pm
Hi,

Assume speed of boy = b
Speed of car = c

time = distance/speed = 10/b = 25/c
=> b/c= 10/25

distance by b = time taken by c for travelling 1000 mtr * speed of b
time by c = 1000/c

Distance by b = 1000/c*b
1000*10/25 = 400 mtr

By the way what are the options.

Regards,
Kapil
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by Jim@StratusPrep » Thu Sep 20, 2012 7:42 am
Just divide 10 by 25 to get .4m
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by Brent@GMATPrepNow » Thu Sep 20, 2012 9:17 am
rrobiinn wrote:If a boy takes as much time in running 10m as a car takes in covering 25m, the distance covered by the boy during the time the car covers 1km, is what?
Whenever you can rephrase a question to read, "For every X something else happens", we can typically solve the question using equivalent ratios.

Here, we have "For every 10m a boy travels, a car travel 25m"
Here, we're comparing the boy's distance to the car's distance.
We want to know the number of meters the boy travels during the time the car travels 1km (1000m).

Let B = the number of meters the boy travels during the time the car travels 1000m

Equivalent ratios
boy's distance/car's distance: __ 10/25 = B/1000

To solve, cross multiply to get: 25B = (10)(1000)
Solve for B to get B=400m

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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