u can solve it by algebra...
but i suppose putting values will make it even more easy..

Let original L and B = 10

Area A = LB = 100
New Length L`= 1.1 * 10 = 11
New Breadth B` = .9 * 10 = 9

New Area A` = L` * B` = 99

Diff = A` - A = -1
the -ve sign signifies decrease
since there is a decrease
and the original value is 100

there is a 1 % dec

IMO D

IMO it is 1% decrease.

neerajkumar1_1 wrote:u can solve it by algebra...
but i suppose putting values will make it even more easy..

Let original L and B = 10

Area A = LB = 100
New Length L`= 1.1 * 10 = 11
New Breadth B` = .9 * 10 = 9

New Area A` = L` * B` = 99

Diff = A` - A = -1
the -ve sign signifies decrease
since there is a decrease
and the original value is 100

there is a 1 % dec

IMO D

thank you....but can you explain me in simple method.........

question like this I just test it with simple number.

I used 5x5=25 and matched it with 5(1.1)x5(.9)=(5.5)x(4.5)=24.75

(25-24.75)/24.75 is around 1%. I assumed the answer is D