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What is the best method to solve.. (tricky "could be t

Expert replies
by El Cucu » Fri Jul 10, 2009 9:51 am
Hi Guys!
The following exercise has some variations that confused me. Any way to solve this in a simple way would be very welcome![/img]
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Source: — Problem Solving |

by Ad_Astra_Per_Aspera » Fri Jul 10, 2009 10:27 am
If x>y^2>z^4 which of the following statements could be true ?
I> x>y>z
II>z>y>x
III>x>z>y

IMO plugging numbers is the quickest method for these problems - the key is to *not* only try with +ve numbers only but with fractions and/or negative numbers as well.

statement 1:
pick x=7 y=2 z=1 so its true

statement 2:
pick x=0.2 y=0.5 z=0.6 so its true

statement 3:
pick x=3 y=-2 z = -1 so its true

hence choice E.
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