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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## What is the area of rectangle ABGH? tagged by: BTGmoderatorLU ##### This topic has 1 expert reply and 0 member replies ### Top Member ## What is the area of rectangle ABGH? In the cube above, AH and BG are diagonals and the surface area of side ABFE is 16. What is the area of rectangle ABGH? $$A.\ \ 4\sqrt{2}$$ $$B.\ \ 16\sqrt{2}$$ $$C.\ \ 16+\sqrt{2}$$ $$D.\ \ 16$$ $$E.\ \ 15\sqrt{3}$$ The OA is B. I'm confused with this PS question. Please, can any expert assist me with it? Thanks in advanced. ### GMAT/MBA Expert Legendary Member Joined 14 Jan 2015 Posted: 2667 messages Followed by: 122 members Upvotes: 1153 GMAT Score: 770 LUANDATO wrote: In the cube above, AH and BG are diagonals and the surface area of side ABFE is 16. What is the area of rectangle ABGH? $$A.\ \ 4\sqrt{2}$$ $$B.\ \ 16\sqrt{2}$$ $$C.\ \ 16+\sqrt{2}$$ $$D.\ \ 16$$ $$E.\ \ 15\sqrt{3}$$ The OA is B. I'm confused with this PS question. Please, can any expert assist me with it? Thanks in advanced. If the figure is a cube, we know that all the sides are equal, (and each face is a square) so if the surface area of ABFE is 16, each side must be 4. We also know that the diagonal of a square splits the square into two 45:45:90 triangles. If triangle ADH is a 45:45:90 triangle, and AD = 4, then we know that AH, the hypotenuse, is equal to 4*âˆš2, as the ratio of the sides of the 45:45:9 triangle is x: x: xâˆš2. If AD = 4 and AH = 4*âˆš2, then rectangle ABGH has an area of 4 * 4*âˆš2 = 16*âˆš2. The answer is B _________________ Veritas Prep | GMAT Instructor Veritas Prep Reviews Save$100 off any live Veritas Prep GMAT Course

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