There are two ways to solve this one,
You could divide the figure into a rectangle + right angle triangle

or

You may apply the formula of areal of a trapezoid

Let's do the 1st one first.
You could divide the figure into a rectangle + right angle triangle

Area
Area of the rectangle + Area of the right angle triangle which is [hight x base] + [\(\frac{1}{2}\) (hight x base)]
= [4x10] + [\(\frac{1}{2}\) x 4 x (13-10)]
= 40 + 2(6)
= 46

Area
formula of areal of a trapezoid =
= \(\frac{1}{2}\) (sum of paralelle sides) (Distance between them)
= \(\frac{1}{2}\) (10 + 13) (4)
= 20 + 26
= 46

Correct answer is B

area=1/2(sum of parallel sides)x(perpendicular distance between the parallel sides)
=1/2(23x4)
=23x2
=46


OA:B