let red jellybeans in jar A=r and yellow jellybeans =y

so red jellybeans in kar b=1.2 r
and yellow=.9y
now r=2y

A toe=r+y=3y

b tot = 1.2r+0.9y=2.4y+0.9y=3.3y

B is lager by =(3.3y-3y)/3y * 100=10%

rahul.s wrote:a grocery store sells 2 varieties of jellybean jars, and each type of jellybean jar contains only red and yellow jellybeans. if jar B contains 20% more red jellybeans than jar A, but 10% fewer yellow jellybeans, and jar A contains twice as many red jellybeans as yellow jellybeans, by what percent is the number of jellybeans in jar B larger than the number of jellybeans in jar A?

sorry, but there are no answer options given.

[spoiler]OA is 10%[/spoiler]

Say Jar A contains x red jelly beans and y Yellow jely bean
Jar B contains 1.2 x red jelly beans and 0.9y yellow jelly beans
x = 2y

Jar A contains 2y+y = 3y jelly beans
Jar B contains 2.4y + 0.9 y = 3.3 y

% by which the number of jellybeans in jar B larger than the number of jellybeans in jar A =100* (3.3y- 3y)/3y = 10%

rahul.s wrote:a grocery store sells 2 varieties of jellybean jars, and each type of jellybean jar contains only red and yellow jellybeans. if jar B contains 20% more red jellybeans than jar A, but 10% fewer yellow jellybeans, and jar A contains twice as many red jellybeans as yellow jellybeans, by what percent is the number of jellybeans in jar B larger than the number of jellybeans in jar A?

sorry, but there are no answer options given.

[spoiler]OA is 10%[/spoiler]

Red Yellow Total
Jar A R Y R+Y
Jar B 1.2R 0.9Y 1.2R +0.9Y

Now R =2Y
-->
Jar A 2Y Y 3Y
Jar B 2.4Y 0.9Y 3.3Y

B is larger than A by % = [(3.3Y-3Y)/3Y] x100 = 10%