Well Gmatmachoman asked me to answer this question.
Conclusion: Any star that does not contain lithium -> not a brown dwarf
Premise: All stars, except brown dwarfs, are hot enough to destroy lithium completely.
Please note: the statements with hydrogen are just background information. Remember, our conclusion does not depend on the background info but is based on the premise.
Make a probability indicator in the conclusion: ANY
A-> None of the brown stars are hot enuf to burn the lithium completely. The probability indicator - None makes the author to draw a conclusion on ALL/ ANY star that does not contain lithium. Correct
B-> The first thing i noticed in this answer choice was the probability indicator- Most. Remember the conclusion draws a statement on ANY star. this is an extrapolation and does not stand true.
for eg: suppose there are 100 students in a college.
Most implies atleast 51. so lets suppose that 51 students drink coffee.
With this information can i conclude that all the 100 students drink coffee?
Well answer choice B makes this mistake. Hence Eliminated!
C-> Brown dwarfs capable of destroying helium is not our point of issue. Note that the conclusion talks about only lithium and not helium.
D-> This does not matter. Let them be formed with the same percent of lithium but whether all brown dwarf stars use up the lithium completely or not is the question at issue. Eliminated!
E->Let brown dwarfs be similiar to red dwarfs in terms of appearance. does it mean they all extinguish the lithium resources completely? remember all that glitters is not gold. just becoz something is similiar to gold in appearance, can we determine that both the objects are gold? Eliminated!
@ Dana, what is the source of this question? interesting one!