Firstly don't assume w to be a integer since its not mentioned.

So if u take w = -1.2

Statement 1
w + 2 = -1.2 + 2 = 0.8 > 0

Statement 2
w^2 = (-1.2)^2 = 1.44 > 1

So clearly w can be < 1.

Hence E)

Stm I

w > -2

INSUFF

Stmt II

|w| > 1

w> 1 or w < -1

INSUFF

Together

w> -2

w^2 > 1

Take w = -1.5 > -2 w^2 > 1 NO
Take w = 2 2>-2 w^2>1 YES

Choose E)

As usual with the GMAT trap, w could be a fraction as well as integer.
Clear E.

cramya wrote:Stmt II

|w| > 1

w> 1 or w < -1

INSUFF

cramya,
i hv ques here.
w^2 >1
then w>1 is ok
and w>-1 but as per u, it wil be w <-1
howcm..cn u explain.

cramya,
i hv ques here.
w^2 >1
then w>1 is ok
and w>-1 but as per u, it wil be w <-1
howcm..cn u explain.

w^2 > 1

|w| > 1

case 1(w positive):

w > 1

case 2: (w negative)

-w > 1

Divide by -1 inequality reverses

w < -1

Hope this helps!

Regards,
CR

(1) w+2>0


-2-----------------------> INSUF


(2) w^2>1

<--------------- - 1 + 1 -----------------------> INSUF

Together

-2 ----- -1 + 1------------------------> It still can be between -2 and - 1

E

logitech wrote:(1) w+2>0


-2-----------------------> INSUF


(2) w^2>1

<--------------- - 1 + 1 -----------------------> INSUF

Together

-2 ----- -1 + 1------------------------> It still can be between -2 and - 1

E

yeah, its best to visualize inequalities on the number line, wherever possible

I thought that answer would be B. The question is asking whether w greater than 1?
If we state that the w will be less than 1, it is an answer to the question. Is it not?

this question only fools you once. Then from here on you will always look for the integers at the top.

Nate

HI All!

still not sure why I get confused on the feasability of stmt 2.
It says x>1 and x<1. So x is >1, correct? If so stmts 2 should be correct.

Is this what I'm missing?? : stmt 2 is saying instead x>1 OR x<1

Thanks![/i]

ironsferri wrote:HI All!

still not sure why I get confused on the feasability of stmt 2.
It says x>1 and x<1. So x is >1, correct? If so stmts 2 should be correct.

Is this what I'm missing?? : stmt 2 is saying instead x>1 OR x<1

Thanks![/i]

stm2 is saying x>1 OR x<-1

So we are not sure if the valuewould be >1

Hope this helps!!

Hi ironsferri,

kvcpk is correct.

Whenever you have two inequalities that can't mutually coexist (ie, w can't be greater than 1 and less than -1 at the same time), then you have alternative inequalities rather than joint inequalities.

So, how can w^2 be greater than 1? Only if w^2 is greater than 1.

And w^2 will be greater than 1 when |w| is greater than 1. So, either w is greater than 1 OR less than -1. (It is very helpful to plot this out on the number line).