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by shashank.ism » Tue Feb 09, 2010 1:15 pm
Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of

18%
20%
21 %
23%
Cannot be determined

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by komal » Tue Feb 16, 2010 11:53 am
shashank.ism wrote:Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of

18%
20%
21 %
23%
Cannot be determined

[spoiler]note: vodka enjoy it :)[/spoiler]
Let the CP of two vodkas be Rs 100 and Rs 100x and individual profit in Rs on them being A and B.
=> (A+2B)/3 = 10/100*(100+200x)/3 and (2A+B)/3 = 20/100*(200 + 100x)/3. solving we get
A = (70+20x)/3 and B = (20x-20)/3
=> profit percentages on each is (70+20x)/3 and (20x-20)/3x. When they are increased to 4/3 and 5/3 times respectively and mixed in the ratio 1:1 we get total profit % as
(4/3*100*(70+20x)/3 + 5/3*100x*(20x-20)/3x)/(100+100x) = 100*(20x+20)/(100+100x) = 20.

Hence, choice (b) is the right answer
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