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If \(\dfrac2{x+1}=\dfrac1{x-1},\) for \(x \ne 1\) and \(x \ne -1,\) then \(x =\)

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Re: If \(\dfrac2{x+1}=\dfrac1{x-1},\) for \(x \ne 1\) and \(x \ne -1,\) then \(x =\)

by Nirav Umaretiya » Sat Sep 12, 2020 9:19 pm
It's a simple arithmetic problem

\(\dfrac2{x+1}=\dfrac1{x-1}\)

So, 2(x-1) = 1(x+1)

So, 2x - 2 = x + 1

So, x = 3

Correct ans is E
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Re: If \(\dfrac2{x+1}=\dfrac1{x-1},\) for \(x \ne 1\) and \(x \ne -1,\) then \(x =\)

by Scott@TargetTestPrep » Mon Sep 14, 2020 4:09 am
Gmat_mission wrote: ↑
Thu Sep 10, 2020 12:39 am
 If \(\dfrac2{x+1}=\dfrac1{x-1},\) for \(x \ne 1\) and \(x \ne -1,\) then \(x =\)

A. -3
B. -2
C. 0
D. 2
E. 3

Answer: E

Solution:

Cross-multiplying, we have:

2x - 2 = x + 1

x = 3

Answer: E

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[email protected]

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