Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby,

[BTGmoderatorDC]

Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

(A) p/2 - 10
(B) 3p/4 - 5
(C) 3p/2 - 5
(D) 5p/4 - 10
(E) 5p - 5


OA B

Source: Princeton Review

[swerve]

Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

(A) p/2 - 10
(B) 3p/4 - 5
(C) 3p/2 - 5
(D) 5p/4 - 10
(E) 5p - 5


OA B

Source: Princeton Review

We can try as follows

\(A + B = p \quad (1)\)
\(B = A + 10 \quad (2)\)

Subtract (2) from (1)
\(A = p + A - 10\)
\(2A = p - 10\)
\(A = \dfrac{p}{2} - 5\)

Now plug this in
\(C = \dfrac{p}{4} + A\)

\(C = \dfrac{p}{4} + \dfrac{p}{2} -5\)

\(C = \dfrac{3p}{4} - 5\)

Therefore, B

[Scott@TargetTestPrep]

Together, Andrea and Brian weigh p pounds; Brian weighs 10 pounds more than Andrea. Brian and Andrea's dog, Cubby, weighs p/4 pounds more than Andrea. In terms of p, what is Cubby's weight in pounds?

(A) p/2 - 10
(B) 3p/4 - 5
(C) 3p/2 - 5
(D) 5p/4 - 10
(E) 5p - 5


OA B

Solution:

We can let A, B, and C be the weights of Andrea, Brian, and Cubby, respectively. We can create the equations:

A + B = p

B = A + 10

and

C = A + p/4

Substituting A + 10 for B in the first equation, we have:

A + A + 10 = p

2A = p - 10

A = p/2 - 5

Now, substituting p/2 - 5 for A in the third equation, we have:

C = p/2 - 5 + p/4

C = 3p/4 - 5

Answer: B