There are 10 players in a chess group, and each player plays each of the others once. Given that each game is played by

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There are 10 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?

A. 10
B. 30
C. 45
D. 60
E. 90

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
Source: — Problem Solving |

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Vincen wrote:
Sun May 03, 2020 12:04 pm
There are 10 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?

A. 10
B. 30
C. 45
D. 60
E. 90

[spoiler]OA=C[/spoiler]

Source: Veritas Prep
Given the information, we can get that each player has to play 9 games; thus, there are 10*9 = 90 games. However, since each game is played between two players, in the count of 90, each game is counted twice; thus, there are 90/2 = 45 games.

The correct answer: C

Hope this helps!

-Jay
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Vincen wrote:
Sun May 03, 2020 12:04 pm
There are 10 players in a chess group, and each player plays each of the others once. Given that each game is played by two players, how many total games will be played?

A. 10
B. 30
C. 45
D. 60
E. 90

[spoiler]OA=C[/spoiler]

Source: Veritas Prep

The total number of games played is 10C2 = (10 x 9)/2! = 45.

Answer: C

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