Drop a perpendicular from point B on the ground; say that point is B' and say that BB' = y feet. We have to get the value of y.
Let's take each statement one by one.
1) Point C is 40 feet above the ground.
Again, drop a perpendicular from point C on the ground; say that point is C'; thus, CC' = 40 feet.
Say AC = 2x, thus, AB = 2x/2 = x
Thus, ∆ABB' and ∆ACC' are similar triangles.
=> 40/y = 2x/x => y 20. Sufficient.
2) \(x=60\)
Certainly insufficient.
The correct answer: A
Hope this helps!
-Jay
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