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If mn ≠0, is m > n?
(1) 1/m < 1/n
(2) m^2 > n^2
OA E
Source: Manhattan Prep
(1) 1/m < 1/n
(2) m^2 > n^2
OA E
Source: Manhattan Prep
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$$m,n\,\, \ne 0$$BTGmoderatorDC wrote:If mn ≠0, is m > n?
(1) 1/m < 1/n
(2) m^2 > n^2
Source: Manhattan Prep
Target question: Is m > n?BTGmoderatorDC wrote: ↑Sat Dec 22, 2018 5:28 amIf mn ≠0, is m > n?
(1) 1/m < 1/n
(2) m^2 > n^2
OA E
Source: Manhattan Prep
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