If x and y are integers

[massi2884]

If x and y are integers, is X > Y?

1) x + y > 0
2) y^x < 0

OA C

[aneesh.kg]

Statement(1):
x + y > 0
This can be true for (x,y) = (4,-2) or (-2, 4)
INSUFFICIENT

Statement(2):
y^x < 0
Any positive number raised to any power is always positive.
For the above statement to hold true, y has to be negative (y < 0) and x has to be an odd integer.
If y = -3, x = -7, -5, -3, -1, 1, 3, 5,..
INSUFFICIENT

Let's combine.
If y < 0, and x + y > 0, then x > 0.
If x > 0 and y < 0, then x > y

[spoiler](C)[/spoiler] is the answer

[neelgandham]

If x and y are integers, is X > Y?

1) X + Y > 0

X > -Y (subtracting Y from both sides). It doesn't necessarily mean that X>Y. So, Statement I is insufficient to answer the question.

2) Y^X < 0

Y^X < 0, implies Y is a negative integer and X is an odd integer. It doesn't necessarily mean that X>Y because X can be a negative odd integer less than Y or it can be an odd integer greater than Y. So, Statement II is insufficient to answer the question.

Statement I and II

Y<0 and X>-Y
So, Y<0, -Y>0,and X>-Y.
i.e 0<Y<-Y<X. We can now confirm that X>Y. So, Statement I + II combination is sufficient to answer the question.

Answer C

[Scott@TargetTestPrep]

If x and y are integers, is X > Y?

1) x + y > 0
2) y^x < 0

OA C

Solution:

Question Stem Analysis:

We need to determine whether x > y given that both x and y are integers.

Statement One Alone:

If x = 2 and y = 1, then x > y. However, if x = 1 and y = 2, then x is not greater than y. Statement one alone is not sufficient.

Statement Two Alone:

The only way that y^x < 0 is if y < 0. However, since x can be either positive or negative, we can’t determine whether x > y. Statement two alone is not sufficient.

Statements One and Two Together:

From statement 2, we know that y is negative.From statement 1, we know that x + y > 0, so x must be positive. Thus, x is indeed greater than y. Both statements are sufficient.

Answer: C