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Rectangle ABCD

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Rectangle ABCD

by GmatKiss » Sat Oct 22, 2011 7:42 am
In Rectangle ABCD (BC > AB), E is the point of intersection of diagonals. If (Angle) ABD is twice than (Angle) EAD, what is the value of (Angle) CED?

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 90 degrees
E. 120 degrees
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by neelgandham » Sat Oct 22, 2011 8:26 am
Angle AEB = CED = x (Vertical opposite angles are equal)

Interior angle between two sides of a rectangle = 90 = 2p+p => p = 30

Sum of angles in a triangle AEB = 180 = 2p + 2p + x => 180 = 120 + x => x = 60 Option C
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