A manufacturer produced x percent more video cameras in 1994 than in 1993 and y percent more video cameras in 1995 than in 1994. If the manufacturer produced 1.000 video cameras in 1993, how many video cameras did the manufacturer produce in 1995?
1) xy=20
2) x + y + (xy)/100 = 9.2
This made me learn some things so I copy it to you.
OA: B
Video cameras
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I think the answer should be B.
question stem:
1000----1993
x(1000)/100 + 1000=> 10x +1000 -----1994
y/100(10x+1000) + 10x+1000=> (xy)/10 +10y +10x +1000 =>1995
Statement I
xy=20
we need individual values for x and y.
Insufficient.
Statement II
100x+100y+xy = 9.2*100
100x+100y+xy=920
(xy)/10 +10y +10x +1000 =>1995
(xy+100y+100x)/10 + 1000
920/10 + 1000 = 1092
Hence B is the answer.
What's the OA?
question stem:
1000----1993
x(1000)/100 + 1000=> 10x +1000 -----1994
y/100(10x+1000) + 10x+1000=> (xy)/10 +10y +10x +1000 =>1995
Statement I
xy=20
we need individual values for x and y.
Insufficient.
Statement II
100x+100y+xy = 9.2*100
100x+100y+xy=920
(xy)/10 +10y +10x +1000 =>1995
(xy+100y+100x)/10 + 1000
920/10 + 1000 = 1092
Hence B is the answer.
What's the OA?
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- Legendary Member
- Posts: 1153
- Joined: Wed Jun 20, 2007 6:21 am
- Thanked: 146 times
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pepeprepa I am more interested in the above statement rather than the question.pepeprepa wrote:This made me learn some things so I copy it to you.
Would love to know those things.
Thanks.
Could you please show me how the bolded statement was created?parallel_chase wrote:I think the answer should be B.
question stem:
1000----1993
x(1000)/100 + 1000=> 10x +1000 -----1994
y/100(10x+1000) + 10x+1000=> (xy)/10 +10y +10x +1000 =>1995
Statement I
xy=20
we need individual values for x and y.
Insufficient.
Statement II
100x+100y+xy = 9.2*100
100x+100y+xy=920
(xy)/10 +10y +10x +1000 =>1995
(xy+100y+100x)/10 + 1000
920/10 + 1000 = 1092
Hence B is the answer.
What's the OA?