IMO E

Case a)

Let price of both computers be p1= 100 dollars and p2= dollars ...

Let t1=10 % t2= 5 %
So Cost of computer in state A > Cost of computer in state B

Now , if p1= 100 and p2 = 200

T1= 10% T2 = 5%

So, cost of computer in state B > Cost of computer in State A

Case b

P1 T1 > P2 T2

Let p1= 100 t1 = 5 500 > 400
p2 = 200 t2 = 2

Cost of computer State B > Cost of computer in state A

Let p1=200 t1=3
Let P2 = 100 t2 = 2

600>200

So Cost of computer State A > Cost of computer in state B

So, insufficient

Now lets combine

t1 > t2

p1t1 > p2t2

in the above examples we have taken these 2 cases already...

So E