please solve it step by step

P(dark chocolate or nuts) = (total dark chocolate + milk chocolate with nuts)/(total candies). The value in blue will account for all of the candies that are BOTH dark chocolate AND nut-filled. Total dark chocolate = 20. Milk chocolate candies with nuts = 20% of 25 = 5. Total candies = (total dark chocolate) + (total milk chocolate) = 20+25 = 45. Thus: P(dark chocolate or nuts) = (20+5)/45 = 25/45. The correct answer is C.

GMATGuruNY wrote:P(dark chocolate or nuts) = (total dark chocolate + milk chocolate with nuts)/(total candies). The value in blue will account for all of the candies that are BOTH dark chocolate AND nut-filled. Total dark chocolate = 20. Milk chocolate candies with nuts = 20% of 25 = 5. Total candies = (total dark chocolate) + (total milk chocolate) = 20+25 = 45. Thus: P(dark chocolate or nuts) = (20+5)/45 = 25/45. The correct answer is C. here we have dark chocolates=20(4 with nuts and 16 without nuts) Milk chocolate candies= 25(5 with nuts and 20 without nuts) now he asked dark chocolate or nuts meaning dark+nuts(milk+dark)-dark with nuts. I'm confused with the question wording.

Mechmeera wrote:GMATGuruNY wrote:P(dark chocolate or nuts) = (total dark chocolate + milk chocolate with nuts)/(total candies). The value in blue will account for all of the candies that are BOTH dark chocolate AND nut-filled. Total dark chocolate = 20. Milk chocolate candies with nuts = 20% of 25 = 5. Total candies = (total dark chocolate) + (total milk chocolate) = 20+25 = 45. Thus: P(dark chocolate or nuts) = (20+5)/45 = 25/45. The correct answer is C. here we have dark chocolates=20(4 with nuts and 16 without nuts) Milk chocolate candies= 25(5 with nuts and 20 without nuts) now he asked dark chocolate or nuts meaning dark+nuts(milk+dark)-dark with nuts. I'm confused with the question wording. Your approach is correct. The colored portion = 20 + (4+5) - 4 = 25. Since 25 of the 45 nuts will yield a favorable outcome, P = 25/45.