veritas prep question

statement II if we take values in fractions

x=-0.5, y = 0.3 x+y = -0.2 xy = -0.15 x+y < xy

x = -0.5, y = 2 x+y = 1.5 xy = -1 then x+y > xy

so insufficient

statement I mode of x = y
x= -0.5 and y = 0.5 x+y = 0 xy = -0.25 x+y > xy
x = -0.5 naad y = -0.5 x+y = -1 xy = 0.25 x+y <xy
insufficient

how it is C

If I get it correct, mode of x is x itself. Problem does not make sense

hmboy17 wrote:DS question-
is x+y > xy?
1) mode of x = y
2) x<0<y

Ans please?
I guess 2 is itself to answer this question
exp- if x= -2 y= 3
then x+y > xy ( 1 > -6)
but the OA is C. aNY ONE EXPLAIN.

You can only have the mode of a set. There's no such thing as "the mode of a number".

Even if we could take the mode of a number (which I maintain that we can't and is a nonsensical idea), it would have to be the number itself; however, statement (2) clearly states that x does NOT equal y.