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veritas#53

Expert replies
Source: — Data Sufficiency |

by KrazyKarl » Mon Aug 30, 2010 9:23 pm
I think it's D.

Statement 1 is sufficient because a^2 is at minimum 0 and that would be greater than -5.

Statement 2 is sufficient because if a>5 then a^2 is bigger than 3*a (the first is a * something bigger than 5, the second is a * 3) and b^4 is at minimum 0 so you're even subtracting something from the smaller number. The answer is Yes for both.
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by Rahul@gurome » Mon Aug 30, 2010 10:22 pm
pradeepkaushal9518 wrote:is a^2>3a-b^4?

1.3a-b^4=-5
2.a>5 and b>0
(1) 3a + 5 = b^4
Question reduces to: Is a ^2 > -5? Since a^2 will always be positive so a^2 > 3a-b^4 is true.
Hence (1) is SUFFICIENT.

(2) a > 5 and b > 0 implies if a = 6 and b = 1, a^2 = 36 and 3a-b^4 = 17; here a^2>3a-b^4 is true.
If a = 7 and b = 10, a^2 = 49 and 3a-b^4 = 21 - 10000 = negative value; here also a^2>3a-b^4 is true.
So, (2) is SUFFICIENT.

The correct answer is [spoiler](D)[/spoiler].
Rahul Lakhani
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by pradeepkaushal9518 » Tue Aug 31, 2010 8:12 pm
thanks rahul . how do u find veritas questions? is they are well enough for gmat level?
A SMALL TOWN GUY
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by Rahul@gurome » Tue Aug 31, 2010 10:45 pm
pradeepkaushal9518 wrote:thanks rahul . how do u find veritas questions? is they are well enough for gmat level?
You are welcome Pradeep. It would not be appropriate for me to comment on another company's material. However, I would recommend using the OG12 questions as your best practice resource. The OG questions are typically the closest to actual GMAT questions.
Rahul Lakhani
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by pradeepkaushal9518 » Wed Sep 01, 2010 12:07 am
ya i understand rahul. i got veritas books from veritas so just posting questions. thanks for great suggestion.
A SMALL TOWN GUY
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