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Variation

This topic has 1 expert reply and 4 member replies
k_suraj786 Newbie | Next Rank: 10 Posts Default Avatar
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Variation

Post Sat Apr 22, 2006 9:23 am
For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

1. One
2. Two
3. Three
4. Four
5. Five
Rolling Eyes

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Post Sun Sep 24, 2017 5:16 am
k_suraj786 wrote:
For a finite sequence of non zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3, 2, 5, -4, -6 ?

1. One
2. Two
3. Three
4. Four
5. Five
We're asked to look at every pair of CONSECUTIVE numbers. If the product of that pair is NEGATIVE, this counts as one variation.

Let's examine the pairs of consecutive numbers:

1 and -3: product is negative
-3 and 2: product is negative
2 and 5: product is positive
5 and -4: product is negative
-4 and -6: product is positive

Since 3 pairs have negative products, the correct answer is C

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Brent

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Post Sat Sep 23, 2017 10:06 pm
from the question, we have this (1, -3, 2, 5, -4, -6).
since we are concern with the variation in sign change, we will have the sequence in this form
1,-3 (+ve to -ve)
-3,2 (-ve to +ve)
-5,4 (-ve t +ve)

therefore, we have three variation.
hence,
option C is right

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chix475ntu Junior | Next Rank: 30 Posts Default Avatar
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17 Apr 2006
Posted:
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Post Sat Apr 22, 2006 9:29 am
3 ( 1 * -3 , -3 * 2, 5 * -4)

C

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k_suraj786 Newbie | Next Rank: 10 Posts Default Avatar
Joined
22 Apr 2006
Posted:
8 messages
Post Sun Apr 23, 2006 8:02 am
Hey chix475ntu,

Thanks...!!!

Razz

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abby_g Junior | Next Rank: 30 Posts Default Avatar
Joined
30 Sep 2006
Posted:
24 messages
Upvotes:
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Post Sat Sep 30, 2006 2:36 am
1,-3
-3,2
-5,4

hence C

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