BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

variables

Expert replies
Source: — Problem Solving |

by cramya » Fri Jan 02, 2009 2:50 pm
Lets substitue b's value starting with choice A and see.

b=2

a+b-ab = 0
a+2-2a = 0

a = 2
b=2
a+b-ab=0
Possible

b=1

a+1-a = 0
1 = 0 Not possible

b cannot be 1

Choose B)
Join the discussion

Re: variables

by steveyb » Fri Jan 02, 2009 2:52 pm
[email protected] wrote:16. For any numbers a and b, a • b = a + b – ab.
If a • b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

b
0 = a + b - ab
-b = a - ab
-b = a(1-b)
-b/(1-b) = a

thus, b cannot equal 1, or else the denominator will = 0
Join the discussion

by cramya » Fri Jan 02, 2009 2:54 pm
Stevey,
Good algebric approach!

Regards,
CR
Join the discussion

Re: variables

by Brent@GMATPrepNow » Fri Jan 02, 2009 2:54 pm
[email protected] wrote:16. For any numbers a and b, a • b = a + b – ab.
If a • b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

b
This is a wonderful question.
set a + b – ab = 0
a + b(1-a) = 0 (factor)
b(1-a)=-a
b=-a/(1-a) or b=a/(a-1) (isolate b)

We can set a/(a-1) equal to each of the answer choices and see whether there is a value for a to let b equal each of those values.

Or we can recognize that a/(a-1) can never equal 1 since a can never equal a-1

So the answer is B
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by ronniecoleman » Sun Jan 04, 2009 10:00 pm
. For any numbers a and b, a • b = a + b – ab.
If a • b = 0, which of the following CANNOT be a value of b?
(A) 2
(B) 1
(C) 0
(D) -1
(E) -3/2

IMO B

if a = 1

1+b -b != 0

for any values of b ...
Admission champion, Hauz khaz
011-27565856
Join the discussion