BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Value of y

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 496
Joined: Tue Jun 07, 2011 5:34 amFollowed by: 1 member
Thanked: 38 times

by sl750 » Mon Dec 05, 2011 10:45 pm
x + 2y + 3z = 2 --- i

x + y - z = 0 ----ii

2x + 2y - z = 1 ----iii


Multiply equation ii by 2

2x+2y=2z. Substitute value of 2x+2y in equation iii
2z-z=1 or z=1

x+2y=-1 --- iv
x+y =1 ---v

Solving , we get, y=-2
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Mon Dec 05, 2011 10:48 pm
karthikpandian19 wrote:What is the value of y in the system below?


x + 2y + 3z = 2
x + y - z = 0
2x + 2y - z = 1

(A) -2 (B) -1(C) 0(D) 1(E) 2
Multiplying 2nd equation by 2, 2x + 2y - 2z = 0
Subtracting 2x + 2y - 2z = 0 and 2x + 2y - z = 1, we get,
-z = -1 or z = 1
So, x + 2y = -1 (1st equation) and x + y = 1 (2nd equation)
Subtracting the above equations, we get y = -2

The correct answer is A.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 10
Joined: Mon Dec 05, 2011 3:33 pm

by CollegeKart » Tue Dec 06, 2011 7:59 pm
x + 2y + 3z = 2 - (1)

x + y - z = 0 - (2)

2x + 2y - z = 1 - (3)


eq 2 gives x +y=z - (4)

put value of eq4 in eq 3

2z - z =1 => z = 1

putting value of z in eq 1 we get x + 2y= -1 - (5)

putting value of z in eq 4 we get x + y= 1 - (6)

eq(5) - eq (6)
y = -2
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Tue Dec 06, 2011 9:44 pm
karthikpandian19 wrote:What is the value of y in the system below?


x + 2y + 3z = 2

x + y - z = 0

2x + 2y - z = 1


(A) -2 (B) -1(C) 0(D) 1(E) 2
Subtracting the second equation from the third, we get:
(2x + 2y - z) - (x + y - z) = 1-0.
x+y = 1.

Since the second equation implies that x+y = z, z=1.

The first equation can be rewritten as y + x + y + 3z = 2.
Substituting x+y=1 and z=1 into this equation, we get:
y + 1 + 3(1) = 2.
y = -2.

The correct answer is A.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1