If y = (x^2 - y^2)/(x-y) and (x # y), then what is the value of y ?
1. x + y = 3
2. x - y = -3
pl explain. thanks.
1. x + y = 3
2. x - y = -3
pl explain. thanks.
Given: y = (x² - y²)/(x - y) and x ≠yanjaneiya wrote:If y = (x^2 - y^2)/(x-y) and (x # y), then what is the value of y ?
1. x + y = 3
2. x - y = -3
As x ≠y, (x - y) ≠0 thus we can write,
.... y = (x² - y²)/(x - y) = (x + y)(x - y)/(x - y) = (x + y)
=> x = 0
Statement 1: (x + y) = 3
Thus, y = (x + y) = 3
Sufficient.
Statement 1: (x - y) = -3
We know x = 0 => y = 3
Sufficient.
The correct answer is D.
