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Expert replies
by lukaswelker » Tue Apr 08, 2014 9:59 am
Here's the question;

If X is positive, which of the following could be the correct ordering of; 1/x; 2x and x2(exponent)

I. x2(exponent) < 2x < 1/x
II. x2(exponent) < 1/x < 2x
III. 2x < x2(exponent) < 1/x

• NONE
• 1 only
• 3 only
• 1 and 2 only
• 1, 2, and 3

I tried to substitute with 1 but it didn't give me the correct answer. Any useful tip?
Cheers
Lukas
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Source: — Problem Solving |

by Brent@GMATPrepNow » Tue Apr 08, 2014 10:02 am
If x is positive, which of the following could be the correct ordering of 1/x, 2x and x²?
I. x² < 2x < 1/x
II. x² < 1/x < 2x
III. 2x < x² < 1/x

(A) None
(B) I only
(C) III only
(D) I and II only
(E) I II and III
Let's start by PLUGGING IN some positive values of x and see what we get.

x = 1/2
1/x = 2
2x = 1
x² = 1/4
So, we get x² < 2x < 1/x
This matches statement I.

x = 3/4
1/x = 4/3
2x = 3/2
x² = 9/16
So, we get x² < 1/x < 2x
This matches statement II

x = 3
1/x = 1/3
2x = 6
x² = 9
So, we get 1/x < 2x < x²
NO MATCHES

At this point, the correct answer is either D or E.
If you're pressed for time, you might have to guess.

Alternatively, you can use some algebra to examine statement III (2x < x² < 1/x)
Notice that there are 2 inequalities here (2x < x² and x² < 1/x)
Take 2x < x² and divide both sides by x to get 2 < x
Take x² < 1/x and multiply both sides by x to get x^3 < 1, which means x < 1
Hmmm, so x is greater than 2 AND less than 1. This is IMPOSSIBLE, so statement III cannot be true.

Answer = D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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