alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1

Excellent question, I think answer is E
but will be pleased if somebody can please explain a quick way to solve it, i just put the values of S in the equation and looked for the biggest value of P but i am not sure that this is the right way to approach a problem like this,
quant whims are welcomed with some explanation......

agree the answer is E

alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1

to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct

diebeatsthegmat wrote:

alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1

to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct

OA is C not E

alivapriyada wrote:

diebeatsthegmat wrote:

alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1

to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct

OA is C not E

Are u sure the answer is C.

Because when s=4 , p =32
when s=1; p= -2(1-4)2+32= 12+32=44

I guess answer must be E.

lokesh r wrote:

alivapriyada wrote:

diebeatsthegmat wrote:

alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1

to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct

OA is C not E

Are u sure the answer is C.

Because when s=4 , p =32
when s=1; p= -2(1-4)2+32= 12+32=44

I guess answer must be E.

yes m sure ,answer is C
this was the explanation provided in the MGMAT

The bus will carry its greatest passenger load when P is at its maximum value. If P = -2(S - 4)2 + 32, the maximum value of P is 32 because (S - 4)2 will never be negative, so the expression -2(S - 4)2 will never be positive. The maximum value for P will occur when -2(S - 4)2 = 0, i.e. when S = 4.

The correct answer is C.

alivapriyada wrote:
yes m sure ,answer is C
this was the explanation provided in the MGMAT

The bus will carry its greatest passenger load when P is at its maximum value. If P = -2(S - 4)2 + 32, the maximum value of P is 32 because (S - 4)2 will never be negative, so the expression -2(S - 4)2 will never be positive. The maximum value for P will occur when -2(S - 4)2 = 0, i.e. when S = 4.

The correct answer is C.

it makes sense how s be negative..
experts comment please........

First I got confused seeing the equation.

I think its (s-4)^2

P = -2(S - 4)^2 + 32

When u sub other values we need to add 32 with one negative value which ll decrease P.

Only S=4 adds 32 with 0 and gives P=32 which is high.

Pick C

I think Selango corrected the equation very well.

It should be P = -2(S - 4)^2 + 32, in this case without any doubt the answer option is C.

Hi alivapriyada, i request you to pls check the question again

and if P = -2(S - 4)2 + 32 is what equation actuall is, as stated by question s is no of stops, so s has to be postivie integer

s=1,2,3,4.....

if s=1,p=44
if s=2,p=40
if s=3,p=36
if s=4,p=32 and so on..

Agreed. Folks, request you to post the questions with the right terminology. It helps save time

Hi guys

sorry to start on this question all over again, but can someone please explain the solution to me step by step?
I really had no idea on how to go about solving it...

Thanks a lot

Kushal

I love it when people post the wrong f**king equation and expect us to come up with the correct answer. Good work.

alivapriyada wrote:

lokesh r wrote:

alivapriyada wrote:

diebeatsthegmat wrote:

alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1

to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct

OA is C not E

Are u sure the answer is C.

Because when s=4 , p =32
when s=1; p= -2(1-4)2+32= 12+32=44

I guess answer must be E.

yes m sure ,answer is C
this was the explanation provided in the MGMAT

The bus will carry its greatest passenger load when P is at its maximum value. If P = -2(S - 4)2 + 32, the maximum value of P is 32 because (S - 4)2 will never be negative, so the expression -2(S - 4)2 will never be positive. The maximum value for P will occur when -2(S - 4)2 = 0, i.e. when S = 4.

The correct answer is C.

so Aliva, is the quoation: p=-2(s-4)^2+32?

@diebeatsthegmat

The correct statement, as u have mentioned, is p = -2(s-4)^2+32

I came across the same question when i took one of the tests...
Can u please explain how u came up with an answer for this question?

Thanks

Kushal