Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

value of n

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 105
Joined: Sat May 17, 2008 8:12 pm
Thanked: 6 times
by gmataug08 » Sat Dec 06, 2008 3:28 pm
Question : For what natural number 'n' is the fraction (3n-4)/5 is an integer?


Options :
A : For n + 3 divisible by 5
B : For n + 1 divisible by 3
C : For even natural ‘n’
D : For 2n + 3 divisible by
E : For n - 3 divisible by 5

OA: A
Top
Join the discussion
Source: — Problem Solving |
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Sat Dec 06, 2008 3:43 pm
Please complete choice D)
Top
Join the discussion
Legendary Member
Posts: 708
Joined: Sun Jun 01, 2008 4:59 amFollowed by: 1 member
Location: USA
Thanked: 13 times

by niraj_a » Sat Dec 06, 2008 4:12 pm
i chose E

if N = 8 then n-3 will be divisible by 5, and so will the term in the original stem
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 105
Joined: Sat May 17, 2008 8:12 pm
Thanked: 6 times

by gmataug08 » Sat Dec 06, 2008 4:13 pm
option D was incomplete .
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 105
Joined: Sat May 17, 2008 8:12 pm
Thanked: 6 times

by gmataug08 » Sat Dec 06, 2008 4:15 pm
niraj_a wrote:i chose E

if N = 8 then n-3 will be divisible by 5, and so will the term in the original stem
that was my answer too. But OA was different, so posted here , incase I missed something (other than the rest of option D)
Top
Join the discussion
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Sat Dec 06, 2008 4:17 pm
So we have 4 choices. ok..

I did it by process of elimination

3n-4/5 = k where k is some integer

3n-4 = 5k

3n-4=0
3n-4=5
3n-4=10(n=2)
3n-4=15
3n-4=20
3n-4=25 (n=7)

The only choices that fits 2 and 7 so far is A)
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 105
Joined: Sat May 17, 2008 8:12 pm
Thanked: 6 times

by gmataug08 » Sat Dec 06, 2008 4:28 pm
if I have n= 8 , E satisfies the condition.

I guess, we have more than one answer. :roll:
Top
Join the discussion
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Sat Dec 06, 2008 4:32 pm
If I have n= 8 , E satisfies the condition.
U r correct. This makes A) fail.

Whats confusing about this question is it akss for one value of n so yes there could be multiple answer choices that satisfy.

Whats the source?
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 119
Joined: Sun Nov 30, 2008 2:47 am
Thanked: 11 times

by Zipper » Sat Dec 06, 2008 5:02 pm
(3n-4)/5=integer

so (3n-4)=units digit 9 or 4

n=3, 8, 13, 18, 23, 28 and so on.

Clearly visible only E fits.

It's not more than one answer since A doesn't even fit. It's clear that this question is very messed up since even the answers are not complete(D).
Top
Join the discussion