A B
+ C
+ D
+ E
_____
A F
_____
In the correctly worked addition problem above, A, B, C, D, E, and F represent six different digits. What is the largest possible value of C?
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
https://www.crushthetest.com
value of C?
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10A+B+C+D+E = 10A +F
B+C+D+E = F
since all are different and F is to be maximized
let B=0
D =1
e =2
F =9
hence, C can be 6.
B+C+D+E = F
since all are different and F is to be maximized
let B=0
D =1
e =2
F =9
hence, C can be 6.
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Clearly the answer is [spoiler]6 [C][/spoiler]
Explanation
=> B+C+D+E <=9
For max C and different BCDEA we have
0+1+2+C = 9
=> C = 6
Hope it helps!!
Explanation
Since A is left unaltered we can conclude that the carry part of addition is 0A B
+ C
+ D
+ E
_____
A F
_____
=> B+C+D+E <=9
For max C and different BCDEA we have
0+1+2+C = 9
=> C = 6
Hope it helps!!
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