Two students \(A\) and \(B\) participate in Physics and Chemistry exams. Each exam subject has \(6\) different exam code

The second student has a 1/6 chance to match the same code in Physics as the first student and a 5/6 chance not to match the same code in Chemistry.
Now, let's calculate the probability that the second student has the same code in Physics but not in Chemistry:
Probability of same code in Physics but not in Chemistry
=1/6 × 5/6
Probability of same code in Physics but not in Chemistry= 5/36

Similarly, the probability that the second student has the same code in Chemistry but not in Physics:
Probability of same code in Chemistry but not in Physics =5/6 ×1/6
Probability of same code in Chemistry but not in Physics= 5/36

Therefore, the total probability is the sum of these two probabilities:
Total probability
5/36 + 5/36
= 10/36
= 5/18
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