Train b is 40 m ahead of train a. Train a is travelling at 60m/h and train b at 50m/h. How long would it take train a to catch train b?
Method one: since the coverage speed is 10m/h and distance to cover is 40m : s=d/t
10=40/t
T=4hrs
Method two:
Only two things which would be equal when both are together would be time so we set up equation:
A. . .. .b
D/s=d/s (since t=d/s)
X/60=(X-40)/50 (let X be distance covered by train a)
50X=60X-2400
X=240 (this is distance that must be covered by train a)
Time taken by train a:
240/60=4 hrs
Method one: since the coverage speed is 10m/h and distance to cover is 40m : s=d/t
10=40/t
T=4hrs
Method two:
Only two things which would be equal when both are together would be time so we set up equation:
A. . .. .b
D/s=d/s (since t=d/s)
X/60=(X-40)/50 (let X be distance covered by train a)
50X=60X-2400
X=240 (this is distance that must be covered by train a)
Time taken by train a:
240/60=4 hrs
