two consecutive odd positive integers

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aarati: Senior | Next Rank: 100 Posts; Posts: 37; Joined: Thu Aug 05, 2010 3:15 am

by aarati » Wed Aug 11, 2010 10:50 pm

Find two consecutive odd positive integers, sum of whose squares is 290.

(a) 19,17
(b) 23,27
(c) 11,-13
(d) 7,9

help me to solve it.......

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Source: Beat The GMAT — Problem Solving | Wed Aug 11, 2010 10:50 pm

clock60: Legendary Member; Posts: 759; Joined: Mon Apr 26, 2010 10:15 amFollowed by: 3 members; Thanked: 85 times

by clock60 » Thu Aug 12, 2010 12:14 am

i got 11 and 13
11^2+13^2=290
but they are not given as answer choices?

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sanju09: GMAT Instructor; Posts: 3650; Joined: Wed Jan 21, 2009 4:27 amFollowed by: 80 members; Location: India; Thanked: 267 times; GMAT Score:760

by sanju09 » Fri Aug 13, 2010 3:40 am

clock60 wrote:i got 11 and 13
11^2+13^2=290
but they are not given as answer choices?

I can sense a typo in choice C there, as it doesn't include consecutive integers, even B doesn't include. Pretty much ambiguous. What is source?

Take away is: Think about two digits that add up to 10.

The mind is everything. What you think you become. -Lord Buddha

Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001

www.manyagroup.com

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