Find two consecutive odd positive integers, sum of whose squares is 290.
(a) 19,17
(b) 23,27
(c) 11,-13
(d) 7,9
help me to solve it.......
(a) 19,17
(b) 23,27
(c) 11,-13
(d) 7,9
help me to solve it.......
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I can sense a typo in choice C there, as it doesn’t include consecutive integers, even B doesn't include. Pretty much ambiguous. What is source?clock60 wrote:i got 11 and 13
11^2+13^2=290
but they are not given as answer choices?