BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

TSD

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times
by sudhir3127 » Mon Aug 25, 2008 6:58 am
Two bodies A and B start from opposite ends P and Q of a straight road. They meet at a point 0.6D from P . Find the point of their fourth meeting.

Answer after some discussion..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Mon Aug 25, 2008 7:03 am
Are you sure that you posted enough information?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

by sudhir3127 » Mon Aug 25, 2008 7:05 am
4meonly wrote:Are you sure that you posted enough information?
Yes i am ... thats all the Question says !!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Mon Aug 25, 2008 7:13 am
Couldn't it be 0.2D?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

by sudhir3127 » Mon Aug 25, 2008 7:17 am
pepeprepa wrote:Couldn't it be 0.2D?
its in fact 0.2D
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Mon Aug 25, 2008 7:22 am
Reasoning please! :D
I've got 0,3D
Last edited by 4meonly on Mon Aug 25, 2008 7:24 am, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Mon Aug 25, 2008 7:23 am
I can't say I used an academic one method, I draw lines with distance 100.
A60 means A is at 60miles, and 60 alone means they meet at 60

First meet:
---------------60----------
We can deduce A speed is 60m/h and B speed is 40m/h

One hour later:
----B20------------A80----

Second meet:
------20--------------------

One hour later:
------A40---------B60-----

Third meet:
--------------------------100

One hour later:
-----A40-------------B60----

Fourth meet:
-----20--------------------
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Mon Aug 25, 2008 7:26 am
pepeprepa wrote:I can't say I used an academic one method, I draw lines with distance 100.
A60 means A is at 60miles, and 60 alone means they meet at 60

First meet:
---------------60----------
We can deduce A speed is 60m/h and B speed is 40m/h

One hour later:
----B20------------A80----

Second meet:
------20--------------------

One hour later:
------A40---------B60-----

Third meet:
--------------------------100

One hour later:
-----A40-------------B60----

Fourth meet:
-----20--------------------
Ye, i have the same logic. But I made a mistake in Third meet
Can we do it through LCM?
I think there should be a solution throught LCM
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

by sudhir3127 » Mon Aug 25, 2008 7:36 am
4meonly wrote:
pepeprepa wrote:I can't say I used an academic one method, I draw lines with distance 100.
A60 means A is at 60miles, and 60 alone means they meet at 60

First meet:
---------------60----------
We can deduce A speed is 60m/h and B speed is 40m/h

One hour later:
----B20------------A80----

Second meet:
------20--------------------

One hour later:
------A40---------B60-----

Third meet:
--------------------------100

One hour later:
-----A40-------------B60----

Fourth meet:
-----20--------------------
Ye, i have the same logic. But I made a mistake in Third meet
Can we do it through LCM?
I think there should be a solution throught LCM
I am not sure how LCMs would work here but there are formula in TSD which might help you..

D + (n-1)2D .......( when 2 bodies are traveling in opposite direction the distance covered by them ...n is the number of trips/ meeting)

Since time is constant...we know the ratio of the speeds

0.6 :0.4
3:2

total distance is D + (4-1)*2D = 7D

we know divide 7D in the ratio of 3:2

therefore A is 4.2 and B is 2.8

thus A having moved a distance of 4.2 will be @ 0.2D from P..

hope this helps..

Thanks pepeprepa.... as usual brilliant !!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Mon Aug 25, 2008 7:46 am
Thanks for posting such brilliant questions Sudhir!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 76
Joined: Sat Aug 02, 2008 10:05 pm
Thanked: 5 times

by rishi235 » Mon Aug 25, 2008 10:11 am
I also got the right answer using pepeprepa's method but took ages to get to the answer
U just gave us a great method sudhir....Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1