AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C? (A) 1 (B) 3 (C) 7 (D) 9 (E) Cannot be determined

Ans would be E. AAA has to be 111 because you cannot get 222 or above by adding two 2digit numbers. Therefore, 13 + 98 = 111 and 17 + 94 = 111. As a result C cannot be determined.

17 94 111 So c is 9 (1 will be the carry over so c will always be 9)

Azanr, Would c not always be 9 in both ur cases?

cramya wrote:Azanr, Would c not always be 9 in both ur cases? Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary

Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary It happens; nice solution though!

adilka wrote:Correct folks. OA is 9, E Answer is 9 (D) was no other value satisfies AAA having to equal 111.

Mr2Bits wrote:adilka wrote:Correct folks. OA is 9, E Answer is 9 (D) was no other value satisfies AAA having to equal 111. How about 84 + 27 74 + 37 Above eqn , equates to 111 Anything wrong in my logic?

piyush_nitt wrote:Mr2Bits wrote:adilka wrote:Correct folks. OA is 9, E Answer is 9 (D) was no other value satisfies AAA having to equal 111. How about 84 + 27 74 + 37 Above eqn , equates to 111 Anything wrong in my logic? Yes your logic is flawed becuase in your case you would be needing to satisfy 888 (AB=84(A=8)) or 777(AB=74(A=7)) The question is asking for two, two digit postive integers when added together equal a 3 digit positve integer where all three digits are the same(this is your A value). Only option is AAA= 111