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by LazySammy » Tue Feb 08, 2011 6:46 pm
What is the least number of digits (including repetitions) needed to express 10 power 100 in decimal notation?
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by Night reader » Tue Feb 08, 2011 7:28 pm
LazySammy wrote:What is the least number of digits (including repetitions) needed to express 10 power 100 in decimal notation?
10^100 [1 AND 100 ZEROS] ---> 101 DIGITS
10^100 ---> 5 DIGITS
10^100= (10^10)^10 ---> 6 DIGITS
10^100= (10^50)^2 ---> 5 DIGITS

IOM 5 DIGITS
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by Anurag@Gurome » Tue Feb 08, 2011 11:42 pm
LazySammy wrote:What is the least number of digits (including repetitions) needed to express 10 power 100 in decimal notation?
10^100 = 1 followed by 100 zeroes
Hence, minimum number of digits required = 1 + 100 = 101
Night reader wrote:10^100= (10^50)^2
This is not decimal representation, it is exponential representation.
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by Night reader » Wed Feb 09, 2011 12:39 am
Thanks Anurag, I put both exponential and decimal above, but incorrectly chosen exponential as 5 digits - it is 101 as you correctly say
Anurag@Gurome wrote:
LazySammy wrote:What is the least number of digits (including repetitions) needed to express 10 power 100 in decimal notation?
10^100 = 1 followed by 100 zeroes
Hence, minimum number of digits required = 1 + 100 = 101
Night reader wrote:10^100= (10^50)^2
This is not decimal representation, it is exponential representation.
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