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Tricky Alligations and Mixtures sum

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by [email protected] » Wed Jun 08, 2011 1:29 am
A butler stole wine from a butt of sherry which contained 40% of spirit and he replaced, what he had stolen by wine containing only 16& spirit. The butt was then of 24% strength only. How much of the butt did he steal?

A] 1:2
B] 1:3
C] 1:4
D] 2:3
E] 3:4

OA later... quite tricky guyzzz.... plzzz explain
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Source: — Problem Solving |

by cans » Wed Jun 08, 2011 1:42 am
let he took x ration butter.
thus remaining =1-x with 40% spirit = .4(1-x) spirit
also he added 16% spirit ie .16x
total = .16x + .4 (1-x) = .24
2x + 5(1-x) = 3 ->x=2/3
IMO D
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by Frankenstein » Wed Jun 08, 2011 1:45 am
Hi,
Concentration of spirit initially = 40%
Concentration of spirit added = 16%
Concentration of spirit in mixture = 24%
So, Volume of wine1/volume of wine2 = (24-16)/(40-24) = 1/2
So, fraction of butt stolen = 2/(2+1) = 2/3

Hence, D
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by [email protected] » Wed Jun 08, 2011 6:02 am
Thanks Cans!! for a wonderful explanation....
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