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Tricky Algebra Question

Problem Solving — algebra and arithmetic
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by milanproda » Mon Dec 20, 2010 1:43 pm
Hello,

I have another Q that I am struggling with:

The relationship between quantities m and n is expressed by the equation 11m=5(n-42). If the difference between the two chosen values of n is 30, what is difference in the corresponding values of m?

A-30/11

B-42/11

C-60/11

D-150/11

E- 14

I am having trouble discerning what the question means by the "two chosen values of n is 30" and how to go about solving for that step.

Thanks !
Milan Prodanovic
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by milanproda » Mon Dec 20, 2010 1:43 pm
Sorry, the answer is D-150/11
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by goyalsau » Mon Dec 20, 2010 8:19 pm
milanproda wrote:Hello,

I have another Q that I am struggling with:

The relationship between quantities m and n is expressed by the equation 11m=5(n-42). If the difference between the two chosen values of n is 30, what is difference in the corresponding values of m?

A-30/11

B-42/11

C-60/11

D-150/11

E- 14

I am having trouble discerning what the question means by the "two chosen values of n is 30" and how to go about solving for that step.

Thanks !
We are given the difference in values of n is 30, try any two values for n , { I choose 0 and 30 }

Substituting n = 0 , 11m=5(n-42)

11(M1) = 5 ( -42 ) ----------------------1


Substituting n = 30 , 11m=5(n-42)

11(M2) = 5 ( -12 ) -------------------------2

Subtract 2 from 1

11 ( M2 - M1 ) = -210 - ( -60 )
( M2 - M1 ) = - 150 /11

Answer is D
Saurabh Goyal
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by milanproda » Tue Dec 21, 2010 3:03 pm
Sorry if I accidently wrote the wrong answer, but the book wrote 150/11 not -150/11. I stupidly put a dash after the letter and the answer (d-150/11). I follow your logic and got the same answer as you. However, the book says 150/11 and not -150/11? Would this change your answer and approach?
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by goyalsau » Tue Dec 21, 2010 9:34 pm
milanproda wrote:Sorry if I accidently wrote the wrong answer, but the book wrote 150/11 not -150/11. I stupidly put a dash after the letter and the answer (d-150/11). I follow your logic and got the same answer as you. However, the book says 150/11 and not -150/11? Would this change your answer and approach?

Substituting n = 0 , 11m=5(n-42)

11(M1) = 5 ( -42 ) ----------------------1


Substituting n = 30 , 11m=5(n-42)

11(M2) = 5 ( -12 ) -------------------------2



Subtract 1 from 2 { Just do the opposite }


11 ( M1 - M2 ) = -60 - ( - 210 )
( M1 - M2 ) = + 150 /11

Answer is D
Saurabh Goyal
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by milanproda » Wed Dec 22, 2010 3:42 am
I did not realize that all I have to do was switch the 60 and 210 to get a positive number. Thank you very much for your help.
Milan Prodanovic
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