Triangle Problem Help

given hypotenuse, h = 10 cm.

Let's say sides be a and b.
We have to find out the perimeter = a + b + h.

Statement (1) gives us (1/2) * a * b = 25.
So we cannot solve for a and b. therefore insufficient.

Statement (2) gives us a = b.
As the triangle is right angled. asq2 + bsq2 = hsq2
gives us a = b = sqrt(5). therefore sufficient.

Let a be the base, b the height and and h the hypotenuse
Then we know h = 10
Also a^2 + b^2 = 100.
Statement 1 says ½ * a * b = 25  ab = 50
Therefore (a+b)^2 = a^2 + b^2 + 2ab = 100 + 2*50 = 200
Or a + b = √200 = 10√2 . Therefore perimeter = 10 + 10√2 . Hence sufficient.

Statement 2 says both sides are equal. Or a=b = 5√2. Therefore perimeter = 10√2 + 10. Hence sufficient.
Answer D.

Agree with choice D as mbadreams, however, he messed up the algebra a bit.

Statement 1: (a+b)^2 = a^2 + b^2 + 2ab = 100 + 2(50) = 200
(a+b)^2 = 200 --> a+b = sqrt(200) = 10*sqrt(2)

Perimiter = a + b + h = 10*sqrt(2) + 10.

Statement 2: 45-45-90 triangle. Each leg is therefore 5*sqrt(2).

Perimeter = 5*sqrt(2) + 5*sqrt(2) + 10 = 10*sqrt(2) + 10

You arrive at choice D.

Thanks mp2437... I think I messed up the calculation in both... the choices.. Thanks so much for noting my mistake... I really need to watch out for those...will edit my reply..

(1)SUFF: 2 equations 2 unknowns
(2)SUFF: 1 equation 1 unknown

Guys, may be a dumb question but I don't see how a^2+b^2=c^2 is the same as (a+b)^2=c^2. Can someone please explain this to me?