Hi there,
I took the Veritas Prep test this morning, which included the following question on the IR section:
For triangle JKL, angle JKL measures 90 degrees, and side JL has a length of 260 centimeters. If side JK > side KL, which of the following could be a combination of the lengths of sides JK and KL?
A) JK:
50
100
120
200
240
B) KL:
50
100
120
200
240
Answer for A): [spoiler] 240
[/spoiler]
Answer for B): [spoiler] 100
[/spoiler]
Since the question says that JK > KL, I knew JK could not be 50 and KL could not be 240 - I knocked down this combination. Then, I used the rule "the sum of any two sides of a triangle must be greater than the third side" to cross off A)/B) combinations 120/50, 120/100, and 200/50.
That left the following options:
A could be 240, in which case Y could be 50/100/120/200
A could be 200, in which case Y could be 50/100/120
At this point, I began using Pythagorean Theorem to figure out the answer but it just became too lengthy and time-consuming. How would I proceed to answer this question in another, more efficient way?
Thank you.
I took the Veritas Prep test this morning, which included the following question on the IR section:
For triangle JKL, angle JKL measures 90 degrees, and side JL has a length of 260 centimeters. If side JK > side KL, which of the following could be a combination of the lengths of sides JK and KL?
A) JK:
50
100
120
200
240
B) KL:
50
100
120
200
240
Answer for A): [spoiler] 240
[/spoiler]
Answer for B): [spoiler] 100
[/spoiler]
Since the question says that JK > KL, I knew JK could not be 50 and KL could not be 240 - I knocked down this combination. Then, I used the rule "the sum of any two sides of a triangle must be greater than the third side" to cross off A)/B) combinations 120/50, 120/100, and 200/50.
That left the following options:
A could be 240, in which case Y could be 50/100/120/200
A could be 200, in which case Y could be 50/100/120
At this point, I began using Pythagorean Theorem to figure out the answer but it just became too lengthy and time-consuming. How would I proceed to answer this question in another, more efficient way?
Thank you.
