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by cubicle_bound_misfit » Sun Sep 14, 2008 5:08 am
Please refer to the problem attached. I can arrive at the solution using clumsy calculation

area = x1(y2-y3) + .... etc

Is there any better way?

please help.
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by niraj_a » Sun Sep 14, 2008 5:23 am
hi there,

shouldn't the answer be 1/3?
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by cubicle_bound_misfit » Sun Sep 14, 2008 5:37 am
Niraj,

Whats your approach?
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by manulath » Sun Sep 14, 2008 5:49 am
Base of both the triangles are on X-axis
hence the value of base can be found by simply deducing the difference between the x-ordinates

the height will be the y-ordinate of the apex.

Triangle PQR: PR=4 (10-6), height =4 (as y-ordinate for Q is 4)
Area = 4*4/2

Triangle LMN: LN = 12 (14-2), height = 12 (as y-ordinate for M is 12)
Area = 12*12/2

Ratio of areas: (4*4/2) / (12*12/2) = 1/9
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by cubicle_bound_misfit » Sun Sep 14, 2008 8:15 am
Gotcha manulath.

Thanks.
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