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Triangle 3 - DS

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by karthikpandian19 » Mon Dec 26, 2011 3:25 am
In the figure above, the coordinates of A and B are (0,p) and (p,q) respectively, where q and p are positive. What is the value of p?

(1) q=3

(2) The area of triangle OAB is 8
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Source: — Data Sufficiency |
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by rijul007 » Mon Dec 26, 2011 4:17 am
karthikpandian19 wrote:In the figure above, the coordinates of A and B are (0,p) and (p,q) respectively, where q and p are positive. What is the value of p?

(1) q=3

(2) The area of triangle OAB is 8
Image

St (1)
q = 3

Doesnt tell us anything about p

Not Sufficient

St(2)

Area = 8

Area = (1/2)* p * p
p*p = 16

Sufficient


Option B
Last edited by rijul007 on Mon Dec 26, 2011 5:19 am, edited 1 time in total.
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by karthikpandian19 » Mon Dec 26, 2011 4:32 am
OA is B


Stat.2
The area of a triangle is ½·Base·Height. p is both the base AO and the height BD of this triangle. The area of OAB is ½·p·p = ½p2 = 8. Now you can calculate p.
rijul007 wrote:
karthikpandian19 wrote:In the figure above, the coordinates of A and B are (0,p) and (p,q) respectively, where q and p are positive. What is the value of p?

(1) q=3

(2) The area of triangle OAB is 8
Image

St (1)
q = 3

Doesnt tell us anything about p

Not Sufficient

St(2)

Area = 8

Area = (1/2)* p * q
p*q = 16

We cant say anything about the value of p

Not Sufficient

Combining St(1) and St(2)

p*q = 16
p = 16/3


Option C
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by rijul007 » Mon Dec 26, 2011 4:45 am
karthikpandian19 wrote:OA is B


Stat.2
The area of a triangle is ½·Base·Height. p is both the base AO and the height BD of this triangle. The area of OAB is ½·p·p = ½p2 = 8. Now you can calculate p.
rijul007 wrote:
karthikpandian19 wrote:In the figure above, the coordinates of A and B are (0,p) and (p,q) respectively, where q and p are positive. What is the value of p?

(1) q=3

(2) The area of triangle OAB is 8
Image

St (1)
q = 3

Doesnt tell us anything about p

Not Sufficient

St(2)

Area = 8

Area = (1/2)* p * q
p*q = 16

We cant say anything about the value of p

Not Sufficient

Combining St(1) and St(2)

p*q = 16
p = 16/3


Option C
Can you please elaborate
I didnt get you
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by karthikpandian19 » Mon Dec 26, 2011 5:10 am
If you see the IMAGE attached to this question showing the triangle, it shows that the Height & Base of the triangle is same.

O is the Origin (0,0)
A is (0,p)
B is (p,q) .......... refer the image

rijul007 wrote:
karthikpandian19 wrote:OA is B


Stat.2
The area of a triangle is ½·Base·Height. p is both the base AO and the height BD of this triangle. The area of OAB is ½·p·p = ½p2 = 8. Now you can calculate p.
rijul007 wrote:
karthikpandian19 wrote:In the figure above, the coordinates of A and B are (0,p) and (p,q) respectively, where q and p are positive. What is the value of p?

(1) q=3

(2) The area of triangle OAB is 8
Image

St (1)
q = 3

Doesnt tell us anything about p

Not Sufficient

St(2)

Area = 8

Area = (1/2)* p * q
p*q = 16

We cant say anything about the value of p

Not Sufficient

Combining St(1) and St(2)

p*q = 16
p = 16/3


Option C
Can you please elaborate
I didnt get you
Image
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Posts: 588
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by rijul007 » Mon Dec 26, 2011 5:16 am
karthikpandian19 wrote:If you see the IMAGE attached to this question showing the triangle, it shows that the Height & Base of the triangle is same.

O is the Origin (0,0)
A is (0,p)
B is (p,q) .......... refer the image

rijul007 wrote:
karthikpandian19 wrote:OA is B


Stat.2
The area of a triangle is ½·Base·Height. p is both the base AO and the height BD of this triangle. The area of OAB is ½·p·p = ½p2 = 8. Now you can calculate p.
rijul007 wrote:
karthikpandian19 wrote:In the figure above, the coordinates of A and B are (0,p) and (p,q) respectively, where q and p are positive. What is the value of p?

(1) q=3

(2) The area of triangle OAB is 8
Image

St (1)
q = 3

Doesnt tell us anything about p

Not Sufficient

St(2)

Area = 8

Area = (1/2)* p * q
p*q = 16

We cant say anything about the value of p

Not Sufficient

Combining St(1) and St(2)

p*q = 16
p = 16/3


Option C
Can you please elaborate
I didnt get you
Image

Oh yea, gotcha

Have to be extra careful :D

Thanks :)
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