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A
B
C
D
E
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Train X leaves New York at 1 A.M. and travels east at a speed of x miles per hour. If train Z leaves New York at 2 A.M. and travels east, at what rate of speed will train Z have to travel in order to catch train X at exactly 5:30 A.M.?
A. 5x/6
B. 9x/8
C. 6x/5
D. 9x/7
E. 3x/2
The OA is D.
Train X travels with a speed of x = d/4.5 (1 a.m. to 5:30 a.m.), train Z travels with a speed of v = d/3.5 (2 a.m. to 5:30 a.m.). Now if d = 4.5{miles}, train X travels with a speed x = 1. Train Z travels with a speed of v = 4.5/3.5 = 9/7.
So, for x = 1, 9x/7 = 9/7. Hence the correct answer is D.
Has anyone another strategic approach to solve this PS question? Regards!
A. 5x/6
B. 9x/8
C. 6x/5
D. 9x/7
E. 3x/2
The OA is D.
Train X travels with a speed of x = d/4.5 (1 a.m. to 5:30 a.m.), train Z travels with a speed of v = d/3.5 (2 a.m. to 5:30 a.m.). Now if d = 4.5{miles}, train X travels with a speed x = 1. Train Z travels with a speed of v = 4.5/3.5 = 9/7.
So, for x = 1, 9x/7 = 9/7. Hence the correct answer is D.
Has anyone another strategic approach to solve this PS question? Regards!






















