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Tough question

Expert replies
by 1947 » Wed Jun 13, 2012 10:01 am
A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?

A $700
B $1000
C $1300
D $1600
E $2000
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Source: — Problem Solving |

by Mike@Magoosh » Wed Jun 13, 2012 3:35 pm
Hi, there. I'm happy to help! :)

First of all, let's consider the revenues. "in 2009 its revenues were 44% higher than in 2007." That's a 44% increase, which means

(2009 rev) = 1.44*(2007 rev)

Well, if we assume a constant rate of growth, a constant percentage, that means the multiplier would be constant each year
(2008 rev) = r*(2007 rev)
(2009 rev) = r*(2008 rev) = (r^2)*(2007 rev)

BIG IDEA: to figure out the single year percent increase from multiple years, you don't take a root of the multi-year percentage, but rather a root of the multi-year muliplier.

r^2 = 1.44
r = 1.2

So the revenue grows 20% a year. That means costs grow at 10% a year.

We know it operated at a $1000 loss in 2007, which means (2007 rev) = (2007 costs) - 1000

(2008 cost) = (2008 rev)
1.1*(2007 cos) = 1.2(2007 rev)
1.1*(2007 cos) = 1.2[(2007 costs) - 1000]
1.1*x = 1.2*(x - 1000)
1.1x = 1.2x - 1200
1200 = 0.1x
12000 = x

The cost in 2007 were $12,000.
The cost in 2008 were 10% greater, #13,200, which were also the revenue in 2008.

Cost in 2009 = 13200*1.1 = 14,520
Revenue in 2009 = 13200*1.2 = 15,840

(2009 profit) = (2009 rev) - (2009 cost)
= 15840 - 14520 = $1320

Hmm. This is close to C, but not exact. I was interpreting growth as a percent growth, and "twice as fast" as double the percent, but now I wonder if that's what the author of the question had in mind. If it's not, then I would argue the question is not clearly written.

I hope that's helpful. Let me know if you have any further questions.

Mike :)
Magoosh GMAT Instructor
https://gmat.magoosh.com/
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by niketdoshi123 » Wed Jun 13, 2012 9:04 pm
1947 wrote: it broke even in 2008
Shouldn't this mean that the firm was still at loss in 2008. But
Mike@Magoosh wrote:
(2008 cost) = (2008 rev)
I am confused!!!
Join the discussion

by GMATGuruNY » Thu Jun 14, 2012 2:43 am
1947 wrote:A firm's annual revenue grows twice as fast as its costs. In 2007 it operated at a $1000 loss, it broke even in 2008, and in 2009 its revenues were 44% higher than in 2007. If the firm's revenues and costs grew at a constant rate over this period, what was its profit in 2009?

A $700
B $1000
C $1300
D $1600
E $2000
Another approach is to guess and check.

Revenues:
An increase of 44% over 2 years implies an increase of 20% each year.
To illustrate:
100 + .2(100) = 120.
120 + .2(120) = 144.
Percent increase = (144-100)/100 = 44%.

Costs:
Since the revenues grow twice as fast as the costs, the costs increase 10% each year.

Since the loss in 2007 is $1000, the revenues and costs in 2007 are almost certainly multiples of 1,000.

Case 1: Revenues in 2007 = 10,000.
Since the loss = 1000, the costs = 11,000.
2008:
Revenues = 10,000 + .2(10,000) = 12,000.
Costs = 11,000 + .1(11,000) = 12,200.
In order to break even, the revenues needs to increase just a bit.

Case 2: Revenues in 2007 = 11,000.
Since the loss = 1000, the costs = 12,000.
2008:
Revenues = 11,000 + .2(11,000) = 13,200.
Costs = 12,000 + .1(12,000) = 13,200. Success!
2009:
Revenues = 13,200 + .2(13,200) = 15,840.
Costs = 13,200 + .1(13,200) = 14,520.
Profit = 15,840 - 14,520 = 1320.

The closest answer is C.
Last edited by GMATGuruNY on Thu Jun 14, 2012 8:22 am, edited 1 time in total.
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by 1947 » Thu Jun 14, 2012 7:12 am
Mike@Magoosh wrote:Hi, there. I'm happy to help! :)


Well, if we assume a constant rate of growth, a constant percentage, that means the multiplier would be constant each year
(2008 rev) = r*(2007 rev)
(2009 rev) = r*(2008 rev) = (r^2)*(2007 rev)
Thanks Mike for pointing out that constant rate of growth means multiplier would be constant each year. Instead I was interpreting that a constant would be added each year i.e.
(2008 rev) = r+(2007 rev)
If my post helped you- let me know by pushing the thanks button. Thanks
Join the discussion

by Mike@Magoosh » Thu Jun 14, 2012 8:54 am
niketdoshi123 wrote:
1947 wrote: it broke even in 2008
Shouldn't this mean that the firm was still at loss in 2008. But
Mike@Magoosh wrote: (2008 cost) = (2008 rev)
I am confused!!!
Dear niketdoshi123

Let's say a company's revenues for a given year are R and their costs for the same year are C.

If C > R, they operate at a loss --- they run a deficit of (C - R)

If C = R, then they break even --- no loss, no profit

If C > R, they operate at a profit, and P = R - C

In this problem, 1947 said "it broke even in 2008", which means in 2008, there was no loss, no profit, and the revenues were exactly equal to the costs. That's why I concluded from that:

(2008 cost) = (2008 rev)

Does this make sense now? Please let me know if you have any further questions.

Mike :)
Magoosh GMAT Instructor
https://gmat.magoosh.com/
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by Mike@Magoosh » Thu Jun 14, 2012 8:55 am
1947 wrote:Thanks Mike for pointing out that constant rate of growth means multiplier would be constant each year. Instead I was interpreting that a constant would be added each year i.e.
(2008 rev) = r+(2007 rev)
You are quite welcome. Best of luck to you, and please let me know if you have any further questions.

Mike :)
Magoosh GMAT Instructor
https://gmat.magoosh.com/
Join the discussion

by 1947 » Thu Jun 14, 2012 9:53 am
Mike@Magoosh wrote:
1947 wrote:Thanks Mike for pointing out that constant rate of growth means multiplier would be constant each year. Instead I was interpreting that a constant would be added each year i.e.
(2008 rev) = r+(2007 rev)
You are quite welcome. Best of luck to you, and please let me know if you have any further questions.

Mike :)
why would the constant rate of growth means multiply by a constant and not add a constant ?
If my post helped you- let me know by pushing the thanks button. Thanks
Join the discussion