touches the length

Let Circle touch AD at Q , CD at R and BC at S

From question stem angle PAO = angle POA = angle PBO = angle POB = 45

Angle AOQ = angle Angle BOS = 45 ( as length of tangents from an external point to a circle are equal )

Angle QOS = 180 ( a strg line)

Angle QOD = Angle DOR ( say x)
Angle ROC = Angle SOC ( say y)
Now since angle QOS = 180 , so 2x + 2y = 180 , gives x + y = 90

X + y is equal to angle of DOC = 90 , hence length of CD = 12^2 + 5^2 = 13

A

rohan_vus wrote:Let Circle touch AD at Q , CD at R and BC at S

From question stem angle PAB = angle POA = angle PBO = angle POB = 45

Angle AOQ = angle Angle BOS = 45 ( as length of tangents from an external point to a circle are equal )

Angle QOS = 180 ( a strg line)

Angle QOS = Angle DOR ( say x)
Angle ROC = Angle SOC ( say y)
Now since angle QOS = 180 , so 2x + 2y = 180 , gives x + y = 90

X + y is equal to angle of DOC = 90 , hence length of CD = 12^2 + 5^2 = 13

A

Please see if the bold contents need some attention.

Edited , but ans still remains the same

rohan_vus wrote:Edited , but ans still remains the same

no issue with your answer, mate